Octahedral molecular geometry describes the shape of compounds wherein six atoms or groups of atoms or ligands are symmetrically arranged around a central atom. Which of the following ligands is most likely to form a low-spin octahedral complex with iron(III)? You may need to download version 2.0 now from the Chrome Web Store. Which of the following shall form an octahedral complex ? o will be discussed in more detail later. Assume that each transition metal ion forms an octahedral complex. Estimation of bonding parameters and overlap integrals in octahedral iron group complexes from magnetic susceptibility and anisotropy data. CoCl 4 2− forms a tetrahedral complex ion and Co(CN) 6 3− forms an octahedral complex ion. Which of the following shell form an octahedral complex 3:02 2.1k LIKES. A.d4(low spin) b.d8(high spin) c.d6 ( low spin) is done on EduRev Study Group by NEET Students. You may need to download version 2.0 now from the Chrome Web Store. These 2 empty d orbitals can undergo sp3d2 hybridisation (or d2sp3 hybridisation) to form octahedral complex. Which of the following shall form an octahedral complex ? Wilkinson’s catalyst react with H 2 to form an octahedral complex in which Rh (Z = 45) has the following electronic configuration in the ligand field ,t 2g 2,2,2, e g 0,0. A. Cloudflare Ray ID: 6162449efbfb4a9e The coordination number of a metal ion in an octahedral complex ion is 8. b. • Which of the following shall form an octahedral complex? Select one: a. Co^2+ b. Mn^3+ c. Cr^2+ Figure 57. ( crystal field stabilisation energy ): HARD. Write down the IUPAC name for each of the following complexes and indicate the oxidation state, electronic configuration and coordination number. Picture Structures 1 and 2 are optical isomers. | EduRev Chemistry Question is disucussed on EduRev Study Group by 151 Chemistry Students. There is only 1 way to fill them, and that is 2 electrons in each of the 5 d-orbitals. Coordination Compounds Multiple Choice Questions and Answers for competitive exams. Structures 3 and 4 are the same complex. 600+ VIEWS. Hybridisation is d2sp3 (octahedral) and the complex is low spin. In d8 (high spin), none of inner d - orbitals is empty. CO In the compound [Ni(en)2(H2O)2]SO4 the oxidation number and coordination number of … • Then which of the following is correct about this new complex ? The octahedron has eight faces, hence the prefix octa-. Which of the following shall form an octahedral complex? Low spin complex of d 6-cation in an octahedral field will have the following energy (Δ o = Crystal field splitting energy in an octahedral field, P= electron pairing energy) All metal ions you have listed CANNOT form both high and low spin octahedral complexes. (Total 4 marks) 20. Also give stereochemistry and magnetic moment of the complex: (i) K[Cr(H 2 O) 2 (C 2 O 4) 2].3H 2 O (ii) [Co(NH 3) … Cu^2+ is d^10, meaning it has 10 electrons in its 5 d-orbitals. All tetrahedral complex ions are low-spin. Please enable Cookies and reload the page. Check Answer and Solution for above Chemistry question - Tardigrade Performance & security by Cloudflare, Please complete the security check to access. Completing the CAPTCHA proves you are a human and gives you temporary access to the web property. A. Co 3+, octahedral complex with weak field ligand. Ni^2+ is d^8, and again, there is only 1 way to fill its d-orbitals, and that is in a high spin configuration. All the ions mentioned in the table form complexes with water (which is a weak ligand) - see this page.. Things are very different in an octahedral complex, like K 4 [Fe(CN) 6]. 13. HARD. 1.7k SHARES. Which one of the following high spin complexes has the largest C.F.S.E. Which of the following statements are true? Question: Which one of the following ions cannot form both a high spin and a low spin octahedral complex ion? Which of the following is diamagnetic in nature? Out of 5 d orbitals, 3 will contains electrons and 2 will be empty. a. Cobalt (III) chloride forms several octahedral complexes with ammonia. Performance & security by Cloudflare, Please complete the security check to access. A metal ion doesn't actually need vacant d orbitals to form a coordination complex according to Crystal field theory. Down the IUPAC name for each of the following will not give test for chloride with., so it is either square planar or tetrahedral short objective type with... Following on the basis of crystal field theory assumes that all bonding between and. Are very important for Board exams as well as competitive exams like IIT-JEE AIIMS! Electron would go into each of the following will not give test for chloride ions with silver nitrate 25! From an octahedral complex, like K 4 [ Fe ( CN 6. Is d2sp3 ( octahedral ) and the complex is an example of octahedral complex 3:02 2.1k LIKES a. 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